[ To match XSL with the good expression XML ]
I take back the collegue's program
In my XML I search to match the XSL only when the paragraph starting by annexe is not in the CELL parent
For exemple :
<BODY>
.............
<CELL>
<PARAGRAPH align="centre">32</PARAGRAPH>
<PARAGRAPH align="centre">annexe V</PARAGRAPH>
</CELL>
.............
<PARAGRAPH align="centre">annexe C</PARAGRAPH>
.............
</BODY>
The actual XSL is (&start-annexe; is just a function to match when the element PARAGRAPH starts by annexe):
<xsl:template match="PARAGRAPH[(@align='center' or @align='left') and &start-annexe;]">
<Annexe>
<xsl:apply-templates select="@*|node()"/>
</Annexe>
</xsl:template>
The actual result is :
<BODY>
.............
<CELL>
<PARAGRAPH align="centre">32</PARAGRAPH>
<ANNEXE>annexe V</ANNEXE>
</CELL>
.............
<ANNEXE>annexe C</ANNEXE>
.............
</BODY>
I would like :
<BODY>
.............
<CELL>
<PARAGRAPH align="centre">32</PARAGRAPH>
<PARAGRAPH align="centre">annexe V</PARAGRAPH>
</CELL>
.............
<ANNEXE>annexe C</ANNEXE>
.............
</BODY>
I tried several possibilities but I don't success...
For exemple
<xsl:template match="PARAGRAPH[(@align='center' or @align='left') and &start-annexe; and not(parent::CELL)]">
Could you help me? Thanks
Answer 1
I believe you are looking for the starts-with function
<xsl:template match="PARAGRAPH[(@align='center' or @align='left')
and starts-with(., 'annexe')
and not(parent::CELL)]">
